b^2+2b=16

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Solution for b^2+2b=16 equation:


Simplifying
b2 + 2b = 16

Reorder the terms:
2b + b2 = 16

Solving
2b + b2 = 16

Solving for variable 'b'.

Reorder the terms:
-16 + 2b + b2 = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + 2b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '16' to each side of the equation.
-16 + 2b + 16 + b2 = 0 + 16

Reorder the terms:
-16 + 16 + 2b + b2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 2b + b2 = 0 + 16
2b + b2 = 0 + 16

Combine like terms: 0 + 16 = 16
2b + b2 = 16

The b term is 2b.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2b + 1 + b2 = 16 + 1

Reorder the terms:
1 + 2b + b2 = 16 + 1

Combine like terms: 16 + 1 = 17
1 + 2b + b2 = 17

Factor a perfect square on the left side:
(b + 1)(b + 1) = 17

Calculate the square root of the right side: 4.123105626

Break this problem into two subproblems by setting 
(b + 1) equal to 4.123105626 and -4.123105626.

Subproblem 1

b + 1 = 4.123105626 Simplifying b + 1 = 4.123105626 Reorder the terms: 1 + b = 4.123105626 Solving 1 + b = 4.123105626 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + b = 4.123105626 + -1 Combine like terms: 1 + -1 = 0 0 + b = 4.123105626 + -1 b = 4.123105626 + -1 Combine like terms: 4.123105626 + -1 = 3.123105626 b = 3.123105626 Simplifying b = 3.123105626

Subproblem 2

b + 1 = -4.123105626 Simplifying b + 1 = -4.123105626 Reorder the terms: 1 + b = -4.123105626 Solving 1 + b = -4.123105626 Solving for variable 'b'. Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + b = -4.123105626 + -1 Combine like terms: 1 + -1 = 0 0 + b = -4.123105626 + -1 b = -4.123105626 + -1 Combine like terms: -4.123105626 + -1 = -5.123105626 b = -5.123105626 Simplifying b = -5.123105626

Solution

The solution to the problem is based on the solutions from the subproblems. b = {3.123105626, -5.123105626}

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